Sunday, February 22, 2009

8. Derivation of the Continuity Equation in Cylindrical Coordinates

This is one of my favorite derivations. Although it would sound a bit intimidating at first, as none of the standard textbooks carry out the derivation in curvilinear coordinates; it is rather easy to obtain. And guess what? the math is quite rewarding!

So we first have to start by selecting a convenient control volume. The idea here is to pick a volume whose sides are parallel per say to the coordinates. For cylindrical coordinates, one may choose the following control volume

control-volume-cylindrical-continuity

Again, as we did in the previous post, we need to account for all the fluid that is accumulating, and flowing through this control volume, namely:

Rate of Accumulation + Rate of Flow In = Rate of Flow Out

First, let’s get some basics laid out. The velocity field will be described as

I always prefer to use u, v, and w instead of ur, utheta, and uz to save on subscripts, although the latter nomenclature is a bit more descriptive… we’ll get used to it. Now, by construction, the volume of the differential control volume is

while the mass of fluid in the control volume is

The rate of change of mass or accumulation in the control volume is then

For the net flow through the control volume, we deal with it one face at a time. Starting with the r faces, the net inflow is

while the outflow in the r direction is

So that the net flow in the r direction is

Being O(dr^2), the last term in this equation can be dropped so that the net flow on the r faces is

The net flow in the theta direction is slightly easier to compute since the areas of the inflow and outflow faces are the same. At the outset, the net flow in the theta direction is

We now turn our attention to the z direction. This requires a little bit of extra work. The most essential ingredient of computing the flow in the z direction is to compute the face areas. As shown in the figure above, the z faces are essentially trapezoids (in the differential limit) and their area is equal to the average of the bases times the height, in other words

then, the inflow at the lower z face is

while the outflow at the upper z face is

Finally, the net flow in the z direction is

Now we can put things together to obtain the continuity equation

dividing by dV and rearranging the r components of the velocity

Voila!


Cite as:
Saad, T. "8. Derivation of the Continuity Equation in Cylindrical Coordinates." Weblog entry from Please Make A Note. http://pleasemakeanote.blogspot.com/2009/02/8-derivation-of-continuity-equation-in.html


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1 comments:

Sepehr said...

Hi

I really need this equation & I dont know for what reason your blog is not working , is there anyway you can fix it or send it to me ????